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2 years ago

5

Matthew uses this scale model of a design he plans to paint on a wall. He uses the key 1 cm = 2.5 ft. One gallon of paint will c

over 400 square feet of wall.
How many gallons of paint will Matthew use?

Enter your answer as decimal in the box.

gal

2 answers:

LUCKY_DIMON [66]2 years ago

7 0

I think it is also 160

Alex787 [66]2 years ago

4 0

Answer:

160 (not sure)

Step-by-step explanation:

400 / 2.5 = 160

160x1 = 160

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80 POINTS HELP<br> 1. What is the value of x? Show all of your work.

AnnyKZ [126]

Answer:

x = 9cm

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

6^2 + x^2 = ( sqrt(117) ^2)

36 + x^2 = 117

Subtract 36 from each side

x^2 = 117 -36

x^2 = 81

Take the square root of each side

sqrt(x^2) = sqrt(81)

x = 9

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3 years ago

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How do you convert 3 into 12/4 and 2 into 16/8?

Monica [59]

Answer:

Step-by-step explanation:

12/4=3 and 16/8=2

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3 years ago

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The Math Club wants to visit a science museum that is 180 miles away from the school. If the club has $150 in its field trip

Arlecino [84]

Well, i depends on how much the van cost bc if you do have enough for the van alone, then you will not have enough for the gas or for snacks for the 180mile drive

4 0

2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

7 0

3 years ago

Plzz anwser ill give brainlest simplify 16- 8/15

Anton [14]

Answer:

232/15 [as an improper fraction] or 15 7/15 [as a mixed fraction]

Explanation:

16 - 8 / 15 =

(16) - (8 / 15) =

((16 × 15) / 15) - ((8) / 15) =

((240) / 15) - ((8) / 15) =

(240 - 8) / 15 =

232 / 15 =

15 7/15

7 0

2 years ago