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Neporo4naja [7]
3 years ago
5

Find ln 0.985 using a calculator and round to four decimal places.

Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

-0.1511

Step-by-step explanation:

uysha [10]3 years ago
6 0

Answer:

-0.1511

Step-by-step explanation:

ln(0.985) is about -0.151136, which, rounded to four decimal places, is -0.1511. Hope this helps!

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What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x​
S_A_V [24]

Answer:

f(g(x))=16x^2+6x-4

Step-by-step explanation:

f(g(x))=4(2x)^2 +3(2x)-4

f(g(x))=16x^2+6x-4

8 0
3 years ago
Eight less thsn a number divided by three is twelve equation pleaseeee
EleoNora [17]
(X/3) - 8 = 12

X being a number divided by 3. This part in parentheses so you solve it first. Subtract 8 from that and your answer equals 12.
6 0
2 years ago
Geometry Math
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Answer:

Step 3: The measure of angle DAB is 60°. Reason: Since DAE is a right angle, and EAB is 30 degrees, 90 - 30 is 60. (Just find the reason that is related to this statement).

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Step-by-step explanation:

6 0
2 years ago
1.4t−0.4(t−3.1)=5.8<br><br> SOLVE FOR Y
VladimirAG [237]
There is no y in this question, however we can solve for t.

1.4t - 0.4(t - 3.1) = 5.8
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3 0
3 years ago
Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

6 0
3 years ago
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