1/y = -3x /2 + 3
mulytiply each term by 2y:-
2 = -3xy + 6y
y = 2 / -3( (x - 2)
y = -0.667 (-2 + x)
Answer:
The distance from the base of the ladder to the base of the house is 10ft
Step-by-step explanation:
From the question, we can gather that the ladder makes a right angle shape with the wall of the house.
The length of this ladder which represents the hypotenuse of the right angled triangle is 26ft while the height of the house to the roof is 24ft
To calculate the distance between the base of the ladder and the base of the house, we shall be employing the use of Pythagoras’ theorem which states that the square of the hypotenuse equals the sum of the square of the 2 other sides
We have established that the hypotenuse is the length of the ladder which is 26ft
Let the distance we want to calculate be d
26^2 = 24^2 + d^2
d^2 = 26^2 -24^2
d^2 = 676 - 576
d^2 = 100
d = square root of 100
d = 10ft
If your looking for greatest common factors they are 1,67, c,and d.
The approximate area in square feet of the sides panel is 146.4 feet.
<h3>
Area = 1 / 2 bh</h3>
where
b = base
h = height
Therefore, let's find the height and the base using trigonometric ratios.
sin 30 = opposite / hypotenuse
sin 30° = h / 26
cross multiply
h = 26 × 1 / 2
h = 13 ft.
Let's find the base using Pythagoras theorem.
b² = 26² - 13²
b² = 676 - 169
b = √507
b = 22.5166604984
b = 22.52 ft
Area = 1 / 2 × 22.52 × 13
Area = 292.76 / 2
Area = 146.38 ≈ 146.4 ft
learn more on right angle triangle here: brainly.com/question/20999524?referrer=searchResults
Answer:
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Step-by-step explanation:
