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Molodets [167]
3 years ago
8

I NEEDZ HELPZZZZZZZZ!!!!btw i didnt mean to click d)20..

Mathematics
1 answer:
joja [24]3 years ago
8 0
The slope is 0 or answer B.)
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10 less than the quotient of g and 3
Phantasy [73]
(g/3)-10 or g÷3-10

This is g divided by 3 minus 10
7 0
3 years ago
QUICKKKKKKK
Stella [2.4K]

Answer:

Steps For Solving Real World Problems

2. Highlight the important information in the problem that will help write two equations.

3. Define your variables.

4. Write two equations.

5. Use one of the methods for solving systems of equations to solve.

6. Check your answers by substituting your ordered pair into the original equations.

4 0
3 years ago
Read 2 more answers
Find the missing probability.<br><br> P(A)=13/20,P(A∩B)=13/25,P(B|A)=?
Tju [1.3M]

By definition of conditional probability,

P(B | A) = P(A ∩ B)/P(A) = (13/25) / (13/20) = 20/25 = 4/5

4 0
3 years ago
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
For which interval does this quadratic inequality hold true?
adoni [48]

Answer:

D

Step-by-step explanation:

x²-4x-12≤0

x²-6x+2x-12≤0

x(x-6)+2(x-6)≤0

(x-6)(x+2)≤0

x=6,-2

∴ value of x lies between -2 & 6

3 0
11 months ago
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