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3 years ago

From the given polygon, find the following:

Mathematics

1 answer:

sweet [91]3 years ago

6 0

1. consecutive sides are thats next to each other so

DE,CD,EF,FG,HG

2. A&B, K& L, C&D, F&E, J&I

3. AB, KL, CD, JI, FE

4.A,B,K,H,G

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What is SIN A?

Bond [772]

Answer:

$\sin A =\frac{4}{5}$

Step-by-step explanation:

Recall the mnemonics SOH CAH TOA.

SOH means the Sine ratio is Opposite over Hypotenuse.

This implies that;

$\sin A =\frac{Opposite}{Hypotenuse}$

The side opposite to angle A is 4cm and the hypotenuse is 5cm.

$\therefore \sin A =\frac{4}{5}$

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3 years ago

How to write 3 turnovers : 12assists as a fraction in simplest form

ArbitrLikvidat [17]

3/ 12 hope this helps as much as it can

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4 years ago

(5x+3y=-3 | 3x – 3y =-21

disa [49]

Answer:

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Step-by-step explanation:

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3 years ago

PQ and QR are 2 sides of a regular 12-sided polygon. PR is a diagonal of the polygon. Work out the size of angle PRQ. You must s

dmitriy555 [2]

Answer:

15°

Step-by-step explanation:

A regular polygon is a polygon in which all the sides and angles of the polygon are equal to each other.

A regular 12-sided polygon is a polygon with 12 equal sides and angles.

The sum of interior angles of a polygon is given as:

sum = (2n - 4)90; where n is the number of sides of the polygon

For a 12 sided polygon:

Sum of interior angles = (2 * 12 - 4)90 = (24 - 4)90 = 20 * 90 = 1800°

Therefore since all the angles are equal, each angle = 1800° / 12 = 150°

Therefore in the question, ∠PQR = 150° (angle of a 12 sided polygon), ∠PRQ = ∠QPR = x

Therefore in triangle PQR:

∠PQR + ∠PRQ + ∠QPR = 180°

150 + x + x = 180

150 + 2x = 180

2x = 30

x = 15°

∠PRQ = 15°

6 0

3 years ago

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

6 0

3 years ago