All categories

3 years ago

What is SIN A?

Mathematics

1 answer:

Bond [772]3 years ago

6 0

Answer:

$\sin A =\frac{4}{5}$

Step-by-step explanation:

Recall the mnemonics SOH CAH TOA.

SOH means the Sine ratio is Opposite over Hypotenuse.

This implies that;

$\sin A =\frac{Opposite}{Hypotenuse}$

The side opposite to angle A is 4cm and the hypotenuse is 5cm.

$\therefore \sin A =\frac{4}{5}$

You might be interested in

(25 points) What is the value of k? Please explain your answer

galben [10]

Answer:

que?

Step-by-step explanation:

6 0

3 years ago

Let p =Vector F G where F(0, 5) and G(–4, –3). What is the direction angle of Negative three-halves p?

Harlamova29_29 [7]

Answer:

63 Degrees

Step-by-step explanation:

Edge 2020

3 0

3 years ago

Read 2 more answers

In a group discussion, which option is most clearly a clarifying question?

Mariulka [41]

Answer:

your answer should be d

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A past survey of students taking a standardized test revealed that % of the students were planning on studying engineering in c

Angelina_Jolie [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval is $-0.00870$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 1068000$

The first proportion $\r p_1 = 0.084$

The second sample size is $n_2 = 1476000$

The second proportion is $\r p_2 = 0.092$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 0.05$

From the normal distribution table we obtain the critical value of $\frac{ \alpha }{2}$ the value is

$Z_{\frac{\alpha }{2} } =z_c= 1.96$

Now using the formula from the question to construct the 95% confidence interval we have

$(\r p_1 - \r p_2 )- z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1} + \frac{\r p_2 \r q_2 }{n_2} }$

Here $\r q_1 = 1 - \r p_1$

=> $\r q_1 = 1 - 0.084$

=> $\r q = 0.916$

and

$\r q_2 = 1 - \r p_2$

=> $\r q_2 = 1 - 0.092$

=> $\r q_2 = 0.908$

$(0.084 - 0.092 )- (1.96)* \sqrt{ \frac{0.092* 0.916 }{1068000} + \frac{0.084* 0.908 }{1476000} }$

$-0.00870$

3 0

3 years ago

to the equation . Where did the student go wrong? Step 1. Factor the polynomial into (x + 6) and (x - 2)Step 2. x - 6 = 0 and x

zvonat [6]

Answer and explanation:

The wrong step is changing the sign in step 2

Such that; in step 1 the student had; (x + 6) and (x - 2)

In step 2, the student should have;

x + 6 = 0 and x - 2 = 0 instead of x - 6 = 0 and x + 2 = 0

Step 3, will thus be;

x = -6 and x = 2

7 0

3 years ago