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Ivan
2 years ago
12

Determine the quadratic equation with roots

Mathematics
1 answer:
zvonat [6]2 years ago
4 0

Answer:

y=6x^2-5x+1

Step-by-step explanation:

If the quadratic equation has a root at \dfrac13 then when x=\dfrac13, y=0

\implies x=\dfrac13

\implies 3x=1

\implies 3x-1=0

If the quadratic equation has a root at \dfrac12 then when x=\dfrac12, y=0

\implies x=\dfrac12

\implies 2x=1

\implies 2x-1=0

Therefore, y=(3x-1)(2x-1)

\implies y=6x^2-5x+1

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Sophie [7]
1)100 or A
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3 years ago
happy paws $17.00 plus $3.50 per hour to keep a dog during the day. Woof charges $11.00 plus $4.75 per hour. complete equeation
yKpoI14uk [10]

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Step-by-step explanation:

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4.75 per hour times the hours, h, plus the fee, 11

4 0
2 years ago
Find the center and the radius of the circle with the equation: <br> x2+6x+y2+4y+12=0
Andrews [41]

Answer:

centre = (- 3, - 2) , radius = 1

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + 6x + y² + 4y + 12 = 0 ( subtract 12 from both sides )

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Use the method of completing the square on the x and y terms

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(3)x + 9 + y² + 2(2)y + 4 = - 12 + 9 + 4

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8 0
3 years ago
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prisoha [69]

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Step-by-step explanation: To find half of the price of $60, simply divide it by 2, which gives you $30.

3 0
2 years ago
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