Answer:
continuously is the most, and what is actually done at the banks...
as for your answer:
<u>Compounded monthly </u>
Step-by-step explanation:
Answer: 20
Step-by-step explanation:
8 times 2 = 16
16 plus 4 = 20
Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is,
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
The answer is number 1. Because 12/10 =20/18 is a true statement. None of the others are true
<h3>
Answer: A) high</h3>
Explanation:
Each set spans from 3 to 7 as the min and max. Since we're dealing with the same endpoints, we have perfect overlap.