-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
-10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28
a=-10
d=-2
xn=a+d(n-1)
the first ten terms are
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28
Answer:
3
x
2
+
2
x
−
2
Step-by-step explanation:
It would take 2.8 hours ((3.5 hours x 2.4 Mph)/3Mph) hours for Max to cover the same route walking 3 mph. This problem can be solved by using the velocity equation which is the velocity is equal a change in position divided by a change of time. The amount of time can be found assuming that Max walks in a constant velocity from the starting point until the finish point of 8.4 miles distance (3.5 hours x 2.4 mph)<span>.</span>
WE NEED THE FREAKIN' POINTS
G(x) = 3x + 1, evaluate g(-2).
Simply plug in (- 3) in g(x)
g(-2) = 3(-2) + 1
g(-2) = - 6 +1
g(-2) = - 5
