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zavuch27 [327]
2 years ago
8

Find an nth degree polynomial function with real coefficients satisfying the given conditions.

Mathematics
1 answer:
damaskus [11]2 years ago
7 0

Step-by-step explanation:

Our roots are 3, and i so our roots form

will be

(x - 3)(x - i)

Since i is one root, it conjugate, must be the other.

so we have

(x - 3)(x - i)(x + i)

Simplify

( {x}^{2}  + 1)(x - 3)

{x}^{3}  - 3 {x}^{2}  + x - 3

So the function is

x {}^{3}  - 3 {x}^{2}  + x - 3

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Rite the first ten terms of a sequence whose first term is -10 and whose common difference is -2.
Lelechka [254]
-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
 -10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28

a=-10
d=-2
xn=a+d(n-1)

the first ten terms are
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28

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3 years ago
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WE NEED THE FREAKIN' POINTS
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