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3 years ago

The graph shows gasoline prices over time. Tell a story about how gas prices change over time.

Mathematics

1 answer:

DochEvi [55]3 years ago

7 0

I'm not sure if this is what you meant, but it was fun to write XD

The market was fairly stable with no problems in the economy and no big political events happening. Then the days started getting colder and people started staying in more- meaning the demand for gas dropped. This eventually it stopped decreasing and stayed like this for a bit until a hurricane is spotted and weather people say it is likely to hit the coast where this gas chart is being charted. The gas prices start increasing, at first its slow as the hurricane gets closer- and it just keeps increasing as people become more and more sure it is going to hit them and they want to evacuate.

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PLZ HELP ANY1!!!!!!!!!!!

Ronch [10]

Its the last one because you plug in the 20(x) for example y=20x
and your table looks like this
x 0/2/4
y 0/40/80 y x
because 20(2)=40 then you would do the same with the rest of the equation
20(4)= 80 there fore the last on is your answer

3 0

3 years ago

The table below shows field goal

nekit [7.7K]

what is the question you are asking

5 0

3 years ago

Suppose the time that it takes a certain large bank to approve a home loan is Normally distributed with mean (in days) μ and sta

kolezko [41]

Answer:

Step-by-step explanation:

Null hypothesis (H0): population mean is equal to 5

Alternate hypothesis (Ha): population mean is greater than 5

Z = (sample mean - population mean) ÷ (sd/√n)

sample mean = 5.3, population mean = 5, sd = 1, n = 500

Z = (5.3 - 5) ÷ (1/√500) = 0.3 ÷ 0.045 = 6.67

Using the normal distribution table, for a one tailed test at 0.01 significance level, the critical value is 2.326

Conclusion:

Since 6.67 is greater than 2.326, reject the null hypothesis (H0)

4 0

3 years ago

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.