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3 years ago

8

Mr.Riley made 21 ounce of potatoes salad to serve to 5 guests at a picnic. If each serving is the same size, how much potato sal

ad will each guest receive

1 answer:

Verizon [17]3 years ago

7 0

Answer:

4.2 ounces

Step-by-step explanation:

21 / 5=4.2

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The pressure, P, of a gas, varies inversely with its volume, V. Pressure is measured in units of Pa. Suppose that a particular a

k0ka [10]

<span>The pressure, P, of a gas, varies inversely with its volume, V
</span>
∴ PV = k where k is constant

<span>The pressure is 84 Pa at a volume of 36 L.
</span>
<span>∴ at P = 84 ⇒⇒⇒ V = 36
</span>
<span>∴ K = PV = 84 * 36 = 3,024 ⇒⇒(1)</span>

If the volume is expanded to 216 L, what will the new pressure be?
We need to find P at V = 216
From the equation (1) ⇒⇒⇒ PV = 3024
substitute with V = 216
∴ 216 P = 3024
∴ P = 3024/216 = 14

The correct answer is option <span>B. 14 Pa</span>

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4 years ago

Solve the equation<br><img src="https://tex.z-dn.net/?f=8%20%2B%209%20%7C7n%20-%206%7C%20%3D%2062" id="TexFormula1" title="8 + 9

laila [671]

$8+9|7n-6|=62\ \ \ |-8\\9|7n-6|=54\ \ \ |:9\\|7n-6|=6\iff7n-6=-6\ \vee\ 7n-6=6\ \ \ |+6\\7n=0\ \vee\ 7n=12\ \ \ \ |:7\\n=0\ \vee\ n=\dfrac{12}{7}$

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3 years ago

In Bluepoint, the average low temperature for January was 40 °F. The average low in February was 27% lower. What was the average

yarga [219]

The average low temperature for January was 40 °F - 100%.

The average low in February was x °F - 27% lower, that is 100%-27%=73%.

Write a proportion:

$\dfrac{40}{x}=\dfrac{100}{73},\\ \\x=\dfrac{73\cdot 40}{100},\\\\x=29.2$

Answer: the average low in February was 29.2 °F.

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3 years ago

In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-s

Bond [772]

Answer:

95.44%

Step-by-step explanation:

Mean (m) = 48

Standard deviation (sd) = 9

n = 12

Zscore = (x - m) /sd

X = 30

Zscore = (30 - 48) / 9

Zscore = - 2

X = 66

Zscore = (66 - 48) / 9

Zscore = 2

percentage of daily phone calls numbering between 30 and 66 = P(z < 2) - p(z < - 2)

P(z < 2) = 0.9772

P(z < - 2) = 0.0228

Hence,

0.9772 - 0.0228 = 0.9544

0.9544 * 100% = 95.44

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4 years ago

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acce

g100num [7]

Here is the correct format for the question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then $\dfrac{v(1/4)-v(0)}{1/4 -0} = \Box$ . By the Mean Value Theorem, there is a number c such that 0 < c < $\Box$ with v'(c) = $\Box$ . Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.

Answer:

Step-by-step explanation:

From the information given :

At 2:00 PM ;

a car's speedometer v(0) = 30 mi/h

At 2:15 PM;

a car's speedometer v(1/4) = 50 mi/h

Given that:

v(f) should be the velocity of the car t hours after 2:00 PM

Then $\dfrac{v(1/4)-v(0)}{1/4 -0} = \Box$ will be:

$= \dfrac{50-30}{1/4 -0}$

$= \dfrac{20}{1/4 }$

= 20 × 4/1

= 80 mi/h²

By the Mean value theorem; there is a number c such that :

$\mathbf{0 < c< \dfrac{1}{4}}$ with $\mathbf{v'(c) = \dfrac{v(1/4)-v(0)}{1/4 -0}} \mathbf{ = 80 \ mi/h^2}$

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3 years ago