Answer:
The distance between the two given complex numbers = 9
Step-by-step explanation:
<u><em>Explanation</em></u>:-
<u><em>Step(i):</em></u>-
Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i
Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane
⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and
B = Z₂ = x₂+ i y₂ = 10 -9 i
Let (x₁ , y₁) = ( 9, -9)
(x₂, y₂) = (10, -9)
<u>Step(ii)</u>:-
<em>The distance between the two points are </em>
A B = 
A B = 
AB = 
<em> AB = √81 = 9</em>
<u><em>Conclusion:-</em></u>
The distance between the two given complex numbers = 9
<u><em></em></u>
Answer:
y=-5x-12
y=-0.5x-5
y=-0.5x+0.5
y=-4.5x+3
y=-2x+7
y=2.5x+10
Step-by-step explanation:
1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).
2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.
4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.
5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)
Hope this helped :) Have a great day
3 + [_] ÷ 7 = 9
[_] ÷ 7 = 9 - 3
[_] = 6 x 7
[_] = 42
to check, just put 42 in the empty place and solve
