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bezimeni [28]
2 years ago
12

Adult racehorse weights are normally distributed, with a mean of 500 kg and a standard deviation of 33 kg. Approximately what pe

rcentage of the adult racehorses weigh more than 570 kg?
1.7%
98.3%
93.3%
0.12%
Mathematics
1 answer:
Korolek [52]2 years ago
7 0
Since we know in a standard deviation that mean plus 1 SD is 533 (66%) and 2 SD is 566 (95%) and 570 is slightly more than 566. Then the amount of race horses weighing within 570 is 98.3%. So to find those more than the mean would be 100%-98.3% which is 1.7%
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steposvetlana [31]

There are two triangles here: ABC and ADF. These triangles are similar, and thus proportional. So, we can set up a proportion between the left side of each triangle and the base of each triangle.

AB / AD = BC / DE

4 / (4 + BD) = 5 / 9

---AD is made up of AB and DB. We know AB, but not BD, so we need to find its value to find the length of AD.

5(4 + BD) = 9 x 4

20 + 5BD = 36

5BD = 16

BD = 3.2

AD = AB + BD

AD = 4 + 3.2

AD = 7.2

Hope this helps!

8 0
3 years ago
2/3 as a real number
BaLLatris [955]

Answer:

Yes

Step-by-step explanation:

I don't know the question but 2/3 is a real number.

8 0
3 years ago
What is the algebra expression for this six feet less than the width
Tatiana [17]
So,

"six feet less than"

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w

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4 0
3 years ago
KEVIN'S GAS TANK IS 1/6 FULL. AFTER HE BUYS 14 GALLONS OF GAS, IT IS 3/4 FULL. HOW MANY GALLONS CAN KEVIN'S TANK HOLD?
Reika [66]

\frac 1 6 t  + 14 = \frac 3 4 t


14 = (\frac 3 4 - \frac 1 6)t = (\frac 9{12} - \frac{2}{12}) t = \frac {7}{12} t


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5 0
3 years ago
Read 2 more answers
This will be so helpful right now thank
RoseWind [281]

Answer:

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Step-by-step explanation:

First find the area of Lot X

67 • 70 = 4,690

Subtract the are of Lot X from the total area

8,375 - 4,690 = 3,685

3,685 is the area of Lot Y

Now divide 3,685 by the length of Lot Y : 67

3,685 ÷ 67 = 55

The width of Lot Y is 55 ft.

Hope this helps!

5 0
3 years ago
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