Answer:
B. a reflection across X axis and then a dilation by a scale factor of 1.5
Step-by-step explanation:
As clear from the graph all the coordinates of image 2 are 1.5 times of image 1 so shape 2 is dilated by the scale factor 1.5.
It is evident from the graph that lines AO and A"O"are parallel to each other so shape 2 is the reflection of shape 1.
Now we calculate the magnitude of line AB
m1 = (y2-y1)/(x2-x1)
=(-3+6)/(-4.5=9)
=3/4.5
=1/1.5
=2/3
Next we calculate magnitude m2 of A"B"
m2= (2-4) /(-3+6)
=(-2/3)
Then we know Tan(180-∅) = -tan∅
similarly if m1=(-m2)
then the one line having magnitude m2 is the rotated image through X axis by 180° of the line having magnitude m1.
So the answer is B.
Rounded to the nearest ten-thousand: 20,000
Rounded to the nearest thousand: 24,000
Answer:
5/3
Step-by-step explanation:
2 2/3 * 5/8
~Turn both into improper fractions
8/3 * 5/8
~Multiply
40/24
~Simplify
5/3
Best of Luck!
Answer:
first is 3.5, second is 1
Step-by-step explanation:
-4.5 = x + 2x - 6
-4.5 - 6 = 3x
10.5 = 3x
10.5/3 = x
3.5 = x
2(3.5) - 6
7 - 6
1
The marginal distribution for gender tells you the probability that a randomly selected person taken from this sample is either male or female, regardless of their blood type.
In this case, we have total sample size of 714 people. Of these, 379 are male and 335 are female. Then the marginal probability mass function would be
![\mathrm{Pr}[G = g] = \begin{cases} \dfrac{379}{714} \approx 0.5308 & \text{if }g = \text{male} \\\\ \dfrac{335}{714} \approx 0.4692 & \text{if } g = \text{female} \\\\ 0 & \text{otherwise} \end{cases}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BG%20%3D%20g%5D%20%3D%20%5Cbegin%7Bcases%7D%20%5Cdfrac%7B379%7D%7B714%7D%20%5Capprox%200.5308%20%26%20%5Ctext%7Bif%20%7Dg%20%3D%20%5Ctext%7Bmale%7D%20%5C%5C%5C%5C%20%5Cdfrac%7B335%7D%7B714%7D%20%5Capprox%200.4692%20%26%20%5Ctext%7Bif%20%7D%20g%20%3D%20%5Ctext%7Bfemale%7D%20%5C%5C%5C%5C%200%20%26%20%5Ctext%7Botherwise%7D%20%5Cend%7Bcases%7D)
where G is a random variable taking on one of two values (male or female).
