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3 years ago

15

Find the value of x to the nearest tenth.

1 answer:

Alex73 [517]3 years ago

6 0

64 - 9 = 55 \sqrt{55} = 7.4161984871

7.4161984871/2 ≈3.7

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The figure below is a triangular prism.

katrin2010 [14]

b X H Divided by 2

so 14 X18 = 252 so now divied that by 2 which is 126 cubic centamityers

7 0

2 years ago

Read 2 more answers

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sergejj [24]

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4 0

3 years ago

Write as an expression and simplify:

Bad White [126]

Answer:

(a) The product of the sum of a and b and their difference.

$(a+b)\times{(a-b)}\\=a^2-b^2$

(b) The tripled product of 6a and b².

$3(6a\times{b^2})\\=3(6ab^2)\\=18ab^2$

(c) The difference of the squares of 2m and 7n.

$(2m)^2-(7n)^2\\=4m^2-49n^2$

5 0

4 years ago

Given f(x) = -x - 2, find x when f(x) = 12.

Flauer [41]

Answer:

We substitute

12 = -x - 2

14 = -x or -x = 14

so the answer is -14!

I am in honors high school algebra and I am 11. Trust me bro.

Step-by-step explanation:

3 0

3 years ago

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

6 0

3 years ago