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3 years ago

Do u know something about Find the quotient.?

Mathematics

1 answer:

denis23 [38]3 years ago

3 0

Answer:

17 divided by 3, the quotient is 5

Step-by-step explanation:because 3x5 is 15 and you cannot go furhter than that.

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Describe the congruence transformation that maps quadrilateral ABCD to quadrilateral A'B'C'D'.

umka2103 [35]

Answer:

B) 90 degrees clockwise rotation

8 0

3 years ago

Each figure below is made up of congruent trapezoids. Find the area of each figure.

Mkey [24]

Use the formula a = a+b/2h

8 0

4 years ago

Question: Consider the similarity transformation of ΔABC to produce ΔEDF.

german

Answer:

see the explanation

Step-by-step explanation:

we have triangle ΔABC

step 1

Rotate 90 degrees clockwise ΔABC about point C to obtain ΔA'B'C'

Remember that

A rotation is a rigid transformation

An object and its rotation are the same shape and size, but the figures may be turned in different directions

ΔABC and ΔA'B'C' are congruent

ΔABC≅ ΔA'B'C

step 2

Dilate the triangle ΔA'B'C' to obtain triangle ΔEDF

Remember that

A dilation is a non rigid transformation

A dilation produces similar figures

If two figures are similar, then the ratio of its corresponding angles is proportional and its corresponding angles are congruent

Find the scale factor of the dilation

The scale factor is equal to the ratio of corresponding sides

In this problem

Let

z ----> the scale factor

$z=\frac{ED}{AB}=\frac{DF}{BC}=\frac{EF}{AC}$

Multiply the length sides of triangle ΔA'B'C' by the scale factor z to obtain the length sides of triangle ΔEDF

Note: in this problem the scale factor z is less than 1

That means ----> the dilation is a reduction

3 0

4 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$

At x = $\frac{-1}{2}$ ,

$f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0$

We know that if $f''(a)>0$ then x = a is a point of minima.

So, $x=\frac{-1}{2}$ is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0

3 years ago

Courtlynn combines 7/8 cup sour cream with 1/2 cup cream cheese. She then divides the mixture between 2 bowls. How much mixture

STALIN [3.7K]

$\frac{11}{4}$ this is because when you add $\frac{7}{8}$ and $\frac{1}{2}$ you get $\frac{11}{8}$ which you'd then divide like this

$( \frac{11}{1} ) ( \frac{2}{8})
=( \frac{11}{1} ) ( \frac{1}{4})
= \frac{11}{4}$

If you wanted to simplify that it would be $2 \frac{3}{4}$

4 0

4 years ago