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Leona [35]
3 years ago
8

I always run out of qeustion

Mathematics
2 answers:
mote1985 [20]3 years ago
7 0

Answer:

Well I am sorry

Step-by-step explanation:

Lyrx [107]3 years ago
5 0

Answer:

same here LOL

Step-by-step explanation:

You might be interested in
If 2x – 1 is a factor of 16x4<br> 24x3 + 2x + f, find f.
Nastasia [14]

Answer:

f = -5

Step-by-step explanation:

If 2x – 1 is a factor of 16x4 + 24x3 + 2x + f, find f.

If 2x - 1 = 16x⁴ + 24x³ + 2x + f, find f.

2x - 1 = 0

2x = 1

x = 1/2

Hence

f(1/2) = 16(1/2)⁴ + 24(1/2)³ + 2(1/2) + f

= 16(1/16) + 24(1/8) + 1 + f

= 1 + 3 + 1 + f

= 5+ f

f = -5

7 0
3 years ago
I need help with this
Nata [24]

Answer:

(2,-7)

Step-by-step explanation:

I think its that

6 0
2 years ago
Which fraction is less than 1 chose all of the correct answer, and explain why you chose and write it down and explain your answ
EleoNora [17]

Answer:

(3/4) and (2/3).

Step-by-step explanation:

For a fraction of the form (p / q), the number in front of the division (p) is the numerator. The number after the division (q) is the denominator.

\begin{aligned} \frac{p}{q} \quad \genfrac{}{}{0}{}{(\text{numerator})}{(\text{denominator})}\end{aligned}.

A positive fraction (p/q) (p,\, q > 0) is less than 1 as long as the numerator p is smaller than the denominator q (that is, p < q.) The reason is that as long as p,\, q > 0:

\begin{aligned} & \frac{p}{q} < 1 \\ \iff & (q)\, \left(\frac{p}{q}\right) < (q)\, (1) && (\text{given that $q > 0$}) \\ \iff & p < q\end{aligned}.

For example, in the fraction (2/3), 2 is the numerator while 3 is the denominator. Both the numerator and the denominator are positive, while the numerator 2\! is smaller than the denominator 3\!. Therefore, (2/3) would be less than 1.

6 0
1 year ago
Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
3 years ago
Please help 20 points
S_A_V [24]

Answer:

can you post a clearer picture ?

Step-by-step explanation:

6 0
3 years ago
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