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Colt1911 [192]
2 years ago
10

17. How many rectangular tiles 10 cm by 7 cm will be required to cover a floor 14 m long and 12.5 m broad and what will be the c

ost at 70 per hundred tiles? ​
Mathematics
1 answer:
Rina8888 [55]2 years ago
7 0

Answer:

  • 25,000 tiles are required to cover the floor and cost Rs. 17,500

~

Step-by-step explanation:

  • Length of tile = 10cm
  • Breadth of tile = 7cm

\sf \longrightarrow Area \:  of  \: Tile = L × B

\sf \longrightarrow Area = 10 × 7 = 70  {cm}^{2}

~

  • Length of floor = 14m = 1400cm
  • Breadth of floor = 12.5m = 1250 cm

\sf \longrightarrow Area  \: of  \: floor = 1400 × 1250

\sf \longrightarrow Area =  1750,000  {cm}^{2}

~

Total number of tiles required = Area of floor/area of tile:

\sf \longrightarrow  \dfrac{750,000}{70}

\pmb{\sf \longrightarrow 25,000  \: tiles }

~

\sf \longrightarrow Cost \:  of  \: 100  \: tiles = Rs. 70/-

\sf \longrightarrow Cost \:  of \:  1 \:  tile = 70/100

\pmb{ \sf \longrightarrow Rs.0.5}

~

Cost of 25,000 tiles:

\sf \longrightarrow 25,000 × 0.5

\pmb{\sf \longrightarrow Rs. 17,500}

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