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2 years ago

Which three comparisons are correct?

Mathematics

1 answer:

tatuchka [14]2 years ago

8 0

Answer:

B,C,F

Step-by-step explanation:

That's the answer. Hope that helps.

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Given: Parallelogram KLMN

kozerog [31]

Answer:

Since, KLMN is a parallelogram, then by the property of parallelogram that opposite angles of a parallelogram is equal, therefore ∠N=∠L and ∠M=∠K.

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

F(x)=x and g(x)=f(6x)

scoray [572]

Answer:

number one:....1

number two : 6fx

3 0

3 years ago

What is the equation of the parabola in vertex form with vertex (2,-4) and directrix y=-6

Pachacha [2.7K]

Answer:

$y=\dfrac{1}{8}(x-2)^2-4$

Step-by-step explanation:

The directrix y=-6 is parallel to the x axes, so parabola has equation of the form

$(x-x_0)^2=2px(y-y_0),$

where $(x_0,y_0)$ is the vertex of parabola and p is parabola's parameter.

By the definition, $\frac{p}{2}$ is the distance from the vertex to the directrix, so

$\dfrac{p}{2}=2\Rightarrow p=4$

Hence, the equation of parabola is

$(x-2)^2=8(y+4)$

See attached diagram for the graph of parabola and its directrix.

In vertex form this equation is

$y=\dfrac{1}{8}(x-2)^2-4$

8 0

3 years ago

Beth is putting liquid fertilizer on the plants in 4 flowerpots. her measuring spoon holds 1/8 teaspoon the directions say to pu

VARVARA [1.3K]

20 times 1/8+1/8+1/8+1/8+1/8=5/8 times 4 because of the four pots = 20

5 0

3 years ago

Read 2 more answers

Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin

levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

$3\frac{3}{5}=\frac{18}{5}$ sq meters

Grandmother's wrapping paper:

$1\frac{1}{2}=\frac{3}{2}$ sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

$=\frac{18}{5}+\frac{3}{2}$

$=\frac{36}{10}+\frac{15}{10}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}$

$=\frac{36+15}{10}$

$=\frac{51}{10}$

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0

3 years ago