The pyramid arena in memphis Tennessee is a square pyramid that is 321 feet tall the base has 600 foot sides find the volume of
1 answer:
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Answer:
See below:
Step-by-step explanation:
Hello! My name is Galaxy and I will be helping you today, I hope you are having a nice day!
We can solve this in two steps, Comprehension and Solving. I'll go ahead and start with Comprehension.
If you have any questions feel free to ask away!!
Comprehension
We know according to the laws of geometry that all angles in a triangle add up to 180 degrees.
We also know that in an isosceles angle, the base angles are equation to each other.
Now that we know what we need to know, we can setup an equation.
We can do this because first of all, we know that 2x-6 is one of the angles and as per the base angles of an isosceles triangle we know that both base angles are x, therefore we can add 2x to get 180 degrees.
I'll start solving now.
Solving
We can solve this by using the equation we made above and solving it with algebra.
We know that x is equal to 46.5 degrees. We can check that by inputting it into the equation.
We've proven that our answer is correct by double checking,
Therefore the answer is 46.5!
Cheers!
Answer:
Exercise (a)
The work done in pulling the rope to the top of the building is 750 lb·ft
Exercise (b)
The work done in pulling half the rope to the top of the building is 562.5 lb·ft
Step-by-step explanation:
Exercise (a)
The given parameters of the rope are;
The length of the rope = 50 ft.
The weight of the rope = 0.6 lb/ft.
The height of the building = 120 ft.
We have;
The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;
ΔW₁ = 0.6Δx·x
The work done for the second half, ΔW₂, is given as follows;
ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375
The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375
∴ We have;
W =
The work done in pulling the rope to the top of the building, W = 750 lb·ft
Exercise (b)
The work done in pulling half the rope is given by W₂ as follows;
The work done in pulling half the rope, W₂ = 562.5 lb·ft