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2 years ago

F(x) = 5x2 + 20x - 12 What is the vertex for this

Mathematics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

10+20x-12

20x-2

X=20-2

X=18

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Pls help! What's the answer?

Ivan

Answer:

The answer is b = 8a

Step-by-step explanation:

As, 0 x 8 = 0

2 1/2 = 5/2, 5/2 x 8 = 20

5 x 8 = 40

7 1/2 = 15/2, 15/2 x 8 = 60

10 x 8 = 80

13 1/2 = 27/2, 27/2 x 8 = 108

So all variables "a" when multiplied by 8 will give us the value in "b"

So b = 8a

4 0

2 years ago

Tim needs 18 pens he can buy them in packages of 6 9 or 12 he will buy only one type of package which packages could Tim buy wri

emmainna [20.7K]

Answer:

See below.

Step-by-step explanation:

Either 3 packets of 6 pens or

2 packets of 9 pens.

3 0

2 years ago

Read 2 more answers

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

2 years ago

PLEASE ASAP I WILL MARK BRAINLIST

inessss [21]

Answer:

a. quotient refers to division

3 0

2 years ago

Help me please please

ratelena [41]

When dividing same numbers with different exponents (they’re both 10 so this works different than if they were different numbers) you subtract the top exponent by the bottom exponent. So 15-4=11 ultimately making the solution 10^11. Hope this helps :)

4 0

2 years ago