Answer:
8.03 or 8.035714 and some other numbers that i cant bother to write out. also as a fraction it would be 803/100
Steps:
Use the divisor and find x :
x - 1 = 0 **add 1
x= 1
Now we will use the 1 in dividing:
take the coefficients from in front of all terms
** make sure you include 0's for x^2 and x since you have to have all terms
set it up with a 1 in a box:
1| 1 0 0 1 **bring the first number down
____________
1 **multiply the boxed number by the first number and add it to the second number
1| 1 0 0 1
____+1_____ **repeat with the rest of the terms
1 1
1| 1 0 0 1
___+1_+1_+1
1 1 1 2
**when you're done, use the new numbers to write an equation starting with a term with a degree one less than the previous equation.
**since there is a remainder, rewrite it divided by the original divisor
final answer:
x^2 + x + 1 + (2/ x -1)
Answer:
35+7t
Step-by-step explanation:
7(5t) {If you expand it}
7×5+7×t
35+7t
Answer:
20%
Step-by-step explanation:
2.5 min =(60×2.5)sec=150 sec
30sec to 150sec=30×100/150=20%
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
