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2 years ago

Write the equation in standard form for the circle passing through (7, 1) centered at the origin

Mathematics

1 answer:

Alenkinab [10]2 years ago

4 0

Step-by-step explanation:

the standard form of a circle equation is

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle, and r is the radius.

since the center of this circle is the origin (0, 0), we have the simplified version

x² + y² = r²

to get r² we simply use the given point

7² + 1² = r²

49 + 1 = r²

r² = 50

our equation in standard form is therefore

x² + y² = 50

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2 years ago

Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

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3 years ago

a line with slope 3 passes through point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2

skad [1K]

The y-coordinate is 16

<h3><u>Solution:</u></h3>

Given that a line with slope 3 passes through point (0, 10)

To find the y-coordinate of the point on the line with x-coordinate 2

Which means the point is (2, y)

Let us find the required y co-ordinate using slope formula

<em><u>The slope of line is given as:</u></em>

For a line containing points $(x_1 , y_1)$ and $(x_2 , y_2)$ is given as:

$\text {slope}=m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text {Here } x_{1}=0 ; y_{1}=10 ; x_{2}=2 ; y_{2}=y$

Given that slope "m" = 3

Substituting the values we get,

$\begin{array}{l}{3=\frac{y-10}{2-0}} \\\\ {3=\frac{y-10}{2}} \\\\ {6=y-10} \\\\ {y=10+6=16}\end{array}$

Thus the y-coordinate is 16

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3 years ago

Find the product of the polynomials.

melisa1 [442]

The answer is 8n2 + 26n + 6

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3 years ago

Read 2 more answers

What is the answer to this question?

sukhopar [10]

First plug in f and g:
$3 x^{2} +1- [1-x]$
Then distribute $3 x^{2} +1-1+x$
Combine like terms
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Now plug in 2 for x
$3( 2^{2} )+2$
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Hope that helps

8 0

3 years ago