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3 years ago

-6 + (1\3) word problem

Mathematics

1 answer:

inessss [21]3 years ago

6 0

-6/3 that is the answer

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What is the area to this problem?

Nady [450]

Answer:

56 units²

Step-by-step explanation:

Each triangle has an area that is ...

... A = 1/2bh = 1/2·7·4

There are 4 such triangles, so the total area is ...

... 4A = 4(1/2)·7·4 = 2·7·4 = 56 . . . . units²

_____

An area formula customarily used when the diagonals are pependicular to each other is that the area is half the product of their lengths.

... A = (1/2)d1·d2 = (1/2)·14·8 = 56

6 0

4 years ago

What is the multiplicative inverse 23/7?

Elena-2011 [213]

Answer:

7/23

Step-by-step explanation:

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3 years ago

How many 4/5 cups servings are in 2/5 of a cup of ice cream? ( in simplest fraction from)

Nutka1998 [239]

I Think the answer is B

4 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago

WHOEVER GETS THIS RIGHT IN 3 MINUTES GETS THE BRAINLIEST!! Four times the sum of a number and 15 is at least 120. Let x represen

larisa [96]

Hey there!

Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.

Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

$4(x+15)\geq 120$

Distribute:

$4x + 60 \geq 120$

Subtract:

$4x\geq 60$

Divide:

$x\geq 15$

Your answer is C.

Hope this helps!

7 0

3 years ago