Answer:
It is not a subspace.
Step-by-step explanation:
So, the polynomial degree of at most 3 is given below as;
V = { p (z) = b0 + b1z + b2z^ + ... + bnz^n. |n is less than or equal to 3 and b0, b1, b2,... are integers.
To determine whether a subset is a subspace of Pn, we have to check for the properties below;
(1). Zero vector property : that is, when polynomial, p(z) = 0 and 0 is an integer.
(2). Addition property= here, we have; p(z) + h(z) = (b0 + b1z + b2z^2 +....+ bnz^n) + ( c0 + c1z + c^2z^2 +... + cnz^n). That is the sum of integers.
(3). Scaler multiplication property: the coefficient here may not be real numbers therefore, the condition is not followed here.
Therefore, it is not a subspace of Pn.
Answer:
Then the solution is (-1/4, 3)
Step-by-step explanation:
Start by eliminating the fractional coefficient 1/4: multiply all 3 terms in the second equation by 4. This results in equation (b), below:
4x - 3y = -10 (a)
4x = y -4 (b)
Substitute y - 4 for 4x in equation (a):
y - 4 - 3y = -10
Combining like terms, we get -2y = -10 + 4, or -2y = -6, or y = 3.
Since x = (1/4)y - 1, if y = 3, then x = (1/4)(3) - 1, or x = 3/4 - 1, or x = -1/4
Then the solution is (-1/4, 3)
Answer:
d = 4 units
Step-by-step explanation:
The diameter is twice the radius
d = 2r
d = 2(2)
d = 4 units
Answer: x = -3
Step-by-step explanation:
-3x = 9
9 ÷ -3 = -3
:)
