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2 years ago

What is the common factor of 9 and 12

Mathematics

2 answers:

Wittaler [7]2 years ago

8 0

Answer:

The common factor of 9 and 12 is 3

Step-by-step explanation:

1. List all the factors of both numbers

9:1,3,9

12:1,2,3,4,6,12

Lelu [443]2 years ago

7 0

We found the factors and prime factorization of 9 and 12. The biggest common factor number is the GCF number. So the greatest common factor 9 and 12 is 3.

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2 years ago

400 meters to 350 meters

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2 years ago

Two bikers rode at a constant speed on a 150-meter track. The data here show each biker's distance for a certain part of the rac

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3 years ago

8x + 20y = 20<br> 14x + 35y = k<br> For the above system of equations to be consistent, k must equal

Goshia [24]

Answer:

Step-by-step explanation:

The equations will be "consistent" when they describe lines that are not parallel.

<h3>Slopes</h3>

The slope of a line whose equation is written in this form is the opposite of the ratio of the y-coefficient to the x-coefficient:

line 1 slope = -8/20 = -2/5

line 2 slope = -14/35 = -2/5

These lines have the same slope, so will be parallel unless they have the same y-intercept.

<h3>Y-intercept</h3>

The y-intercept of each line is the ratio of the constant to the y-coefficient:

line 1 y-intercept = 20/20 = 1

line 2 y-intercept = k/35

We want these lines to have the same y-intercept so that they are not inconsistent. This requires ...

k/35 = 1

k = 35

For the equations to be consistent, we must have k = 35.

<em>Additional comment</em>

Linear equations are generally categorized as "consistent" or "inconsistent," and "dependent" or "independent."

Equations are "inconsistent" if there are no values of the variables that satisfy all of the equations. They are "dependent" if they describe exactly the same relation between the variables. "Consistent" equations may be "dependent" (describing the same line, as here), or "independent" (describing lines with different slopes.)

7 0

1 year ago

Timothy is filling fish bowls with pebbles at his fish store. He wants to have $\frac{1}{6}$ of a pound of pebbles in each fish

Luba_88 [7]

Answer:

Step-by-step explanation:

Given that:

Each fish bowl to have pebbles of weight equivalent to = $\frac{1}{6}$

Total pounds of pebbles that Timothy can use = $2\frac{1}{3}$

To find:

The greatest value of Total number of fish bowls that Timothy can fill ?

Solution:

First of all, we need to convert mixed fraction into a fractional number and then we also need to see division of two fractions.

Formula:

$1. \ p\dfrac{q}{r} = \dfrac{p\times r+q}{r}\\2. \ \dfrac{\frac{a}{b}}{\frac{c}d}=\dfrac{a\times d}{b\times c}$

Now, the given mixed fraction can be converted to fractional number as:

$2\dfrac{1}{3} = \dfrac{2\times 3+1}{3} = \dfrac{7}{3}$

Now, To find the total number of fish bowls that can be filled, we need to divide the total number of pounds with number of pounds of pebbles in each fish bowl.

So, the answer is:

$\dfrac{\frac{7}{3}}{\frac{1}{6}}\\\Rightarrow \dfrac{7\times 6}{3\times 1}\\\Rightarrow \dfrac{42}{3}\\\Rightarrow \bold{14}$

<em>14</em> number of fish bowls can be filled.

3 0

2 years ago