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dem82 [27]
1 year ago
7

I need help with this math i am not very good at it

Mathematics
1 answer:
Gwar [14]1 year ago
6 0

Answer:

44 sq. in.

Step-by-step explanation:

Area (total) = (1/2)(3)(4) + 10(3) + (1/2)(8)(2)

= 6 + 30 + 8

= 44 sq. in.

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Complete the equation of the line through (3, -1) and (4, 7)​
nikitadnepr [17]

Answer:

  y = 8x -25

Step-by-step explanation:

The two-point form of the equation of a line can be used.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (7-(-1))/(4-3)(x -3) +(-1)

  y = 8(x -3) -1

  y = 8x -25 . . . . slope-intercept form of the equation

_____

We don't know what you're starting with, so we don't know how to "complete the equation." Perhaps the above equation is sufficient for the task.

4 0
3 years ago
To find the slope of the two points
S_A_V [24]

Answer:

slope is -7/5x-4

Step-by-step explanation:

8 0
3 years ago
A 5 pound bag of apples costs 4.50 and an 8 pound bag of the same type of apples costs 7.52 greg found the unit price which is t
irga5000 [103]

Answer: 0.04 per pound

Step-by-step explanation:

A 5 pound bag of apples costs 4.50.

The unit price will be 4.50 divided by 5 which will be:

4.50 ÷ 5 = 0.9

The unit price is 0.9 per pound

A 8 pound bag of the same type of apples costs 7.52.

The unit price will be 7.52 divided by 8 which will give:

7.52 ÷ 8 = 0.94

The unit price is 0.94 per pound

The difference in the unit prices will be the subtraction of 0.90 from 0.94.

0.94 - 0.90 = 0.04

The difference in the unit prices is 0.04 per pound.

6 0
3 years ago
Rewrite the following integral in spherical coordinates.​
lora16 [44]

In cylindrical coordinates, we have r^2=x^2+y^2, so that

z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}

correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)

which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

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2 years ago
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Elsa is going to buy a truck so she can give down to the good old bar to drink her painful sadness away so that later she'll feel happy enough to take the barrel of gun and put it in her mouth and just starts deepthoarting
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