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gayaneshka [121]
2 years ago
13

If p(x) = 3x³-7x-4 and g(n)-4x^3-7x^2- 2x are polynomials then find the degree of p(x)+q (x)​

Mathematics
1 answer:
Vinvika [58]2 years ago
7 0

Answer:

3.

Step-by-step explanation:

p(x) + q(x)

= -x^3 - 7x^2 - 9x - 4

- whose degree is 3   ( the highest index is 3)

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What precent of 95 is 60.8​
dezoksy [38]

60.8 is 64% of 95.

Step-by-step explanation:

Given number is;

95

We have to find at what percent, the value is 60.8

Let x be the percent.

Therefore;

x% of 95 = 60.8

\frac{95x}{100}=60.8 \\0.95x=60.8

Dividing both sides by 0.95

\frac{0.95x}{0.95}=\frac{60.8}{0.95}\\x=64

60.8 is 64% of 95.

Keywords: percent, division

Learn more about division at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

5 0
3 years ago
Help me find the key to this row of numbers please.
wariber [46]

Answer:

OPTION A .

A.144 PLEASE MARK BRAINLEST

7 0
2 years ago
12. If n(A) = 14, n(B) = 15, and n(<br>AB) = 6, then n(AUB) is<br>​
motikmotik

Answer:

given n(A) = 14

n(B) = 15

n(A∩B ) = 15

Step-by-step explanation:

now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)

n(AUB) = 14+15-6 = 23.Answer

3 0
2 years ago
Read 2 more answers
A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has four identi
Tcecarenko [31]

Answer:

a. 0.1536

b. 0.9728

Step-by-step explanation:

The probability that a component fails, P(Y) = 0.2

The number of components in the system = 4

The number of components required for the subsystem to operate = 2

a. By binomial theorem, we have;

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) is given as follows;

P(Y = 2) = \dbinom{4}{2} × 0.2² × 0.8² = 0.1536

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) = 0.1536

b. The probability that the system last longer than 1,000 hours, P(O) = The probability that no component fails + The probability that only one component fails + The probability that two component fails leaving two working

Therefore, we have;

P(O) = P(Y = 0) + P(Y = 1) + P(Y = 2)

P(Y = 0) = \dbinom{4}{0} × 0.2⁰ × 0.8⁴ = 0.4096

P(Y = 1) = \dbinom{4}{1} × 0.2¹ × 0.8³ = 0.4096

P(Y = 2) = \dbinom{4}{2} × 0.2² × 0.8² = 0.1536

∴ P(O) = 0.4096 + 0.4096 + 0.1536 = 0.9728

The probability that the subsystem operates longer than 1,000 hours = 0.9728

4 0
2 years ago
The product of x and the sum of 6 and 8 times the square of x
Kamila [148]

Let's separate this problem into several parts:

1. The product of x

AND

2. The sum of 6 and 8

TIMES

3. The square of x

So translating this word problem into numbers, we have:

x TIMES (6+8) TIMES x²

so that is:

x * 14 * x²

which is:

14x^(2+1) = 14x³

8 0
3 years ago
Read 2 more answers
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