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2 years ago

Please help … will mark brainliest

Mathematics

1 answer:

vlada-n [284]2 years ago

4 0

Answer:

k = 3

Step-by-step explanation:

Expanding the first term, we find 1/x at 10(kx)²(1/x)³ = 10k²/x

Expanding the first term, we find 1/x at 8*1⁷(-2/x)¹ = -16/x

Then

10k² - 16 = 74

k = 3

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PLEASE HELP

elena-14-01-66 [18.8K]

So if it’s perpendicular you have to have the opposite resipecole and for the original equation I had to move it around because it was in standard form then you answer would be y=3x-24 I know that person on the top is ignorant plus I did the work so just save the photo and turn it in hope this helped have a great day

4 0

2 years ago

Solve the equation for x. Plz help

Art [367]

Answer:

C) 3

Step-by-step explanation:

2(3x-2)=14

6x-4=14

+4 +4

6x=18

6 6

x=3

<h2>I hope that helped!!!</h2>

7 0

3 years ago

of the 75 boys in the 7th grade class, 25 participate in at least one sport . of the 120 girls in 7th grade class 30

hoa [83]

Answer:

"No, the relationship is NOT proportional"

Step-by-step explanation:

<u>Complete Question:</u>

Of the 75 boys in the 7th grade class, 25 participate in at least one sport. Of the 120 girls in 7th grade class 30 participate in at least one sport. Is this relationship proportional?

We have to see the ratio of each and if they are equal (after reducing), we can say they are proportional.

Boys:

25 participate in atleast 1 sport and there are total of 75. Hence, ratio is

25 : 75 = 1 : 3

Girls:

30 particiapte in atleast 1 sport and there are toal of 120. hence ratio is:

30 : 120 = 1 : 4

So, the relationship is NOT proportional

6 0

3 years ago

Lim <br> x → 1 <br> ln(x)/<br> sin(7πx)

mote1985 [20]

$\displaystyle\lim_{x\to1}\frac{\ln x}{\sin7\pi x}$

Note that both the numerator and denominator approach 0 as $x\to1$ , so we can try using L'Hopital's rule.

$\displaystyle\lim_{x\to1}\frac{\lnx }{\sin7\pi x}=\lim_{x\to1}\frac{\frac1x}{7\pi\cos7\pi x}=\lim_{x\to1}\frac1{7\pi x\cos7\pi x}$

The denominator is nonzero at $x=1$ , so the limit is equivalent to

$\displaystyle\frac1{\lim\limits_{x\to1}7\pi x\cos7\pi x}=\frac1{7\pi\cos7\pi}=-\frac1{7\pi}$