Answer:
x≥2
Step-by-step explanation:
12x+6\ge \:9x+12
12x+6-6\ge \:9x+12-6
12x\ge \:9x+6
12x-9x\ge \:9x+6-9x
3x\ge \:6
1. k = 2<span>2.5</span><span>
2. xy=k
thats what i got</span>
Hmm this seem rather complicated would you send me more details
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.