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WINSTONCH [101]
2 years ago
13

If y = lim [-3x^3+2x^2-4x+5] when x--> -2

Mathematics
2 answers:
maks197457 [2]2 years ago
5 0

In this case to calculate the limit, you simply plug the x value of -2 into the function

y =  \lim_{x \to \--2}( -3x^3+2x^2-4x+5) = 24 + 8+8+5 = 45\\

So the limit equals 45.

Hope that helps!

Flauer [41]2 years ago
3 0

Answer:

\displaystyle y = 45

General Formulas and Concepts:
<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                                \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em />\displaystyle y =  \lim_{x \to -2} \big[ -3x^3 + 2x^2 - 4x + 5]

<u>Step 2: Find Limit</u>

  1. [Limit] Limit Rule [Variable Direct Substitution]:                                         \displaystyle y =  -3(-2)^3 + 2(-2)^2 - 4(-2) + 5
  2. Evaluate:                                                                                                       \displaystyle y = 45

∴ the limit as <em>x</em> approaches -2 of the given function -3x³ + 2x² - 4x + 5 is equal to 45.

---

Learn more about limits: brainly.com/question/26091024

Learn more about calculus: brainly.com/question/26752465

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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