Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
I think it is A.
Step-by-step explanation:
happy to help
Answer: x = 13
Step-by-step explanation: When solving an equation like this, we are trying to get our variable which is our letter by itself.
So we first want to ask ourselves what is the 14 doing to <em>x</em>. Well, we can see that it's being added to <em>x</em> so to get <em>x</em> by itself, we will do the opposite of addition which is subtraction. So we subtract 14 from both sides of the equation.
The +14 -14 cancels out so we're left with <em>x</em> on the left.
On the right, we must subtract 14 from 27 to get 13.
So we have x = 13 which is the solution to this equation.
Answer:
60mm/s
Step-by-step explanation:
Plz give brianliest and push the thanks button
Answer:
4/6
Step-by-step explanation:
1/2 needs to be converted to sixths, so we would multiple the numerator and the denominator by 3, because 2 goes into 6, 3 times, then we would get 3/6 + 1/6, then just add, 1 + 3 = 4, and then you end up with 4/6. Have A Great Day!
