Answer with Step-by-step explanation:
a.
Taking both sides log
Using identity:
Using identity:
b.
We know that
Using identity
c.
Substitute the values then we get
By using 
Hence, 
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form.
p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial
This polynomial has a degree of at least 4. It therefore cannot be cubic.
Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do.
(x - 1)(x - 2)(x - 3)
This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct.
Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
Ln x=5-2
ln x=3
ln x is base e log x
so,
x=e^(3)
x=20.0855369232
Answer:
x = -12
Step-by-step explanation:
-2.5(x-4)=-3x+4
Distribute
-2.5x +10 = -3x +4
Add 3x to each side
-2.5x+10 +3x = -3x+4+3x
.5x +10 = 4
Subtract 10 from each side
.5x+10-10=4-10
.5x = -6
Divide by .5
.5x/.5 = -6/.5
x = -12
The midpoint between -4 and 8 is answer B) 2
