20 POINTS WILL MARK BRAINLIEST!!

What is the volume of this?

dangina [55]

the volume is 2040 inches^3

3 0

3 years ago

If x =2/3, what is the value of the following expression? X^3 x 3 divided by 2/9 + 9x - 7-6x

Damm [24]

This is a basic algebraic equation

And will be using PEMDAS to solve

P: Parentheses
E: exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction

If you are unaware of PEMDAS this is the order at which you solve algebraic equation. So start from “P” and end with “S”

X= 2/3

2/3^3 Times 3 Divided by 2/9 + 9(2/3) - 7 - 6(2/3)

Now, personal I’d choose to convert fractions to decimals to simplify solving the equation. I doubt this is the only way to solve for the equation but I find this is the easiest

To convert a fraction to decimal you divide the numerator by the denominator.

So 2/3 is 0.666667
And
That means 2/9 is 0.222222

0.666667^3*3/0.222222+9(0.666667)-7-6(0.666667)

Making you answer roughly -0.999989

Hope this helps, but I’m not sure if this is completely right or not

3 0

3 years ago

A game is played with a played pentagonal spinner with sides marked 1 to 5. The scorer is on the side which comes to rest on the

slava [35]

Answer: probability of getting two 5s =0.04

probability of getting at least one 5 =0.36

probability of getting a total score greater than 5 =0.6

Step-by-step explanation:

Total outcomes on 1 spinner = 5

Then , total outcomes of spinning it 2 times= $5\times5 = 25$

Number of outcomes for getting two 5's = 1

Then, the probability of getting two 5s $=\dfrac{\text{Favorable outcomes of getting two 5's }}{\text{Total outcomes}}$

$=\dfrac{1}{25}=0.04$

Number of outcomes for getting at least one 5 [ {(1,5),(2,5),(3,5),(4,5),(5,5), (5,1), (5,2), (5,3), (5,4)} ] =9

Then, the probability of getting at least one 5 $=\dfrac{\text{Favorable outcomes of getting at least one 5 }}{\text{Total outcomes}}$

$=\dfrac{9}{25}=0.36$

Number of outcomes for getting a total score of 5, [ {(1,4),(4,1),(2,3),(3,2)} ] =4

Then, the probability of getting a total score of 5, $=\dfrac{\text{Favorable outcomes of getting a total score of 5 }}{\text{Total outcomes}}$

$=\dfrac{4}{25}$

Number of outcomes for getting a total score greater than 5 [ {(1,5),(5,1),(2,4),(4,2),(2,5), (5,2), (3,4),(4,3), (3,5), (5,3), (3,3), (4,5), (5,4), (4,4), (5,5)} ] =15

Then, the probability of getting a total score greater than 5, $=\dfrac{\text{Favorable outcomes of getting a total score greater than 5 }}{\text{Total outcomes}}$