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3 years ago

8

If you horizontally stretch the quadratic parent function, f(x) = x2, by a factor of 5, what is the equation of the new function

?
a.g(x) = (5x)2
b.g(x) = x2
c.g(x) = 5x2
d.g(x) = (x)2

2 answers:

vfiekz [6]3 years ago

6 0

None of the above .

A horizontal stretch is given by (1/5)x^2

5x^2 gives a vertical stretch factor 5

lina2011 [118]3 years ago

5 0

Answer:

g(x)=(1/5x)^2

Hope this helps you :)

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Ket [755]

Because the left side is eclipsed in an absolute value, we have two possible values of x, denoted by:
2x+4 = 12 and -(2x+4) = 12

Solving for both of these, we are presented with the two values of x:
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3 years ago

PLEASE HELP ASAP !!

wariber [46]

Answer:

<u>First figure:</u> $954cm^3$

<u>Second figure:</u> $1,508yd^3$

<u>Third figure:</u>

Height= q
Side length = r

<u>Fourth figure: </u> $726cm^3$

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

<u>2. Data:</u>

radius = 9cm / 2 = 4.5cm

length = 15 cm

<u>3. Substitute in the formula and compute:</u>

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

<u>B. Second figure</u>

<u>1. Formula: </u>

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

<u>2. Data:</u>

radius = 12yd

height = 40 yd

<u>3. Substitute and compute:</u>

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

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<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

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The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

<u>2. Data: </u>

height: H = 18cm

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<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) <u>Volume of the pyramid</u>:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

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lina2011 [118]

Answer:

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Check

f(x) = 3x + 4

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Answer:

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