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My name is Ann [436]
3 years ago
11

What is theoretical vs experimental probability? Please help!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

See down below.

Step-by-step explanation:

Theoretical probability is what we expect to happen. For example, we do a test of flipping a coin. You know that its either gonna be heads or tails.

Experimental probability is what actually happens when we try it out. It occurs when we are doing an experiment and then something happens.

Hope this helps!

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1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
A factory produces 2985 bulbs in a day. how many bulbs did it produce in that year.<br><br>​
anastassius [24]

Answer:

1089525

Step-by-step explanation:

2985 is per day of bulbs and a year has 365 days

so we multiply bulbs by day and days in a year

which will give us 1089525

6 0
3 years ago
Read 2 more answers
2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?
Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

  • R is a point on one of the rays forming Angle 1
  • S is a point on the ray that is the opposite of ray VR
  • T is a point on the other ray forming Angle 1
  • U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

7 0
4 years ago
an electronic store had a 20% off sale. If a stareo originally cost $125, how much did the stareo cost during the sale?
spayn [35]

Answer:

100

Step-by-step explanation:

You multiply 125 by 0.80.  This is because 125 is the original amount nd to find out how much you have to pay, you would subtract 20% from 100% to get 80%.  Now, you know that you have to pay for 80% of the stereo.  In order to multiply the two numbers together, you have to convert 80% to a decimal which is 0.80.  Lastly, you multiply to get 1oo.  Therefore, the stereo costs $100.00 during the sale.

6 0
3 years ago
(64a^-6b^12)^5/6<br>simplify the expression
Ray Of Light [21]
\left(64a^{-6}b^{12}\right)^\frac{5}{6}\\\\64=2^6\\\\therefore:\left(2^7a^{-6}b^{12}\right)^\frac{5}{6}\\\\use:(a\cdot b)^n=a^n\cdot b^n\Rightarrow\left(2^6a^{-6}b^{12}\right)^\frac{5}{6}=\left(2^6\right)^\frac{5}{6}\left(a^{-6}\right)^\frac{5}{6}\left(b^{12}\right)^\frac{5}{6}=(*)

use:\left(a^n\right)^m=a^{n\cdot m}\\\\(*)=2^{6\cdot\frac{5}{6}}\cdot a^{-6\cdot\frac{5}{6}}\cdot b^{12\cdot\frac{5}{6}}=2^5\cdot a^{-5}\cdot b^{10}=(**)\\\\We\ know:a^{-n}=\left(\frac{1}{a}\right)^n\\\\therefore:(**)=\boxed{\boxed{\frac{32b^{10}}{a^5}}}
4 0
4 years ago
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