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jarptica [38.1K]
3 years ago
10

Please help just this​

Mathematics
1 answer:
natulia [17]3 years ago
8 0

Answer:

Assuming it’s a matter of rotations.

Since its 180 clockwise you go, well clockwise.

You put your needle on the point of rotation and stretch it to a random point “assuming it’s A”.

You put the pencil on A and needle on the point of rotation (X for now) and then draw a circle.

You then proceed to without changing the compass postion, put it on point A, and construct tiny arcs (like a hexagon), each tic (arc) is 60 degrees so constructed 3 of those. Each time you make an arc, go to the arc you made without changing your compass and repeat until 3 times.

On the third arc mark (assuming A), A prime or A'.

You then put your needle on (x) again then put the lead on lets say point B.
You repeat the steps until all points have a prime (').
You then just construct the primed letters and then connect them with a straight edge.
You now have a 180 degree clockwise rotation.


(if your trying to find which one looks like it, then its usually one who’s straight up flat on the same plane AKA a reflection)

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If m = -3 then what is the value of -2m^3
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Answer : 54

-2(-3^3)

Calculate within parenthesis : (-3^3) = -27

Multiply and divide left to right : -2(-27) = 2*27 = 54

I hope this helps


7 0
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What is the answer to this equation?
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3 years ago
URGENT PLZ HELP VERY VERY URGENT HELP PLEASE I BEG CORRECT ANSWER PLZ
rusak2 [61]

Answer:

<u>Given is the piecewise function</u>

<h3>The first interval</h3>

<u>Domain:</u>

  • x ≤ -2

<u>The function</u>

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<h3>The second interval</h3>

<u>Domain</u>

  • -2 < x ≤ 0

<u>The function</u>

  • The slope is m = (0 - (-4))/(0 - (-2)) = 4/2 = 2
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<h3>The third interval</h3>

<u>Domain</u>

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<u>The function</u>

  • The slope is m = (0 - 2)/(4 - 0) = - 1/2
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6 0
3 years ago
Y=x^2+2x+1 find the vertex
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I'm going to put this into vertex form, which is y=a(x-h)^2+k

To do this, you use completing the square. Start by subtracting 1 from each side

-1+y=x^2+2x

Then, divide b (2) by 2 and square it. Add that number to each side. (normally when you complete the square, you take out the gcf of the right side of the equation before you do this. Then, you would multiply (b/2)^2 by the gcf before adding it to the left side. Since there is no gcf, we do not have to worry about this)

2/2=1
1^2=1
-1+1+y=x^2+2x+1

Next, simplify the left side and factor the right side.

y=(x+1)^2

This is vertex form. a=1, h=-1, and k=0

The vertex is (h,k) so it is (-1,0)

hope this helps!
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