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Dahasolnce [82]
3 years ago
14

Miranda's chocolate bar is in the shape of a triangular prism. She cuts her chocolate bar parallel to its bottom. The dotted lin

e in the picture represents Miranda’s cut.
What is the shape of the cross section of Miranda’s cut?

trapezoid


triangle


rectangle

rhombus

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0
Rectangle trust me

Thank me later
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A plane averaged 500 mph on a trip going east, but only 200 mph on the return trip. The total flying time in both directions was
adoni [48]

Let's assume time taken by plane on one way distance as 't'

The total flying time in both directions was 10.5 hr

so, time taken in other direction =10.5-t

now, we are given

A plane averaged 500 mph on a trip going east

so, total distance of one way is

=500t

total distance of other way is

=200(10.5-t)

now, we can that distance is same from both sides

so, we get

500t=200(10.5-t)

now, we can solve for t

500t=2100-200t

700t=2100

t=3

now, we can find one way distance

=500\times 3

=1500miles..............Answer

6 0
3 years ago
Help my semester ends in 17 hours
Nata [24]
Find the lengths of the sides. Determine how long a right triangle side lengths are.
4 0
2 years ago
Math help please? <3
Tomtit [17]
10m + 80 = P
where every month he gets 10, and for 6 months, he now has 60
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7 0
4 years ago
Read 2 more answers
Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'
AleksandrR [38]
Let's start by assuming Armando's house is between Joey's and the park. 

Let x be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. 

</span>\dfrac{9}{10} = x + \dfrac{3}{5}

x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}

That's probably the answer they're looking for.  But what if the park is between Joey and Armando's houses or Joey is between the park and Armando?  (The latter isn't really possible with the given distances.)

Let a, b, c be the distances between three collinear points like we have here.  Our equation is really a few equations in one, something like

\pm a \pm b = \pm c

Let's get rid of the plus/minuses. Squaring,

a^2 + b^2\pm 2ab = c^2

\pm 2ab = c^2-a^2-b^2

4a^2b^2 = (c^2-a^2-b^2)^2

For us, that's a quadratic equation for c^2

4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2

I'll skip right to the solutions,

c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}


c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0
4 years ago
Hey help please math I need help good luck I’ll I’ve point
fredd [130]

Answer:

180 degrees

Step-by-step explanation:

180 degrees would flip the triangle halfway through a full circle. B is A upside down rotated halfway through a full circle.

7 0
3 years ago
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