Question

What is the expression obtained when the sum of 2a−16abc−45 and 2a+7abc+11 is subtracted from 6a+6abc−30?​

Answer 1

Answer:

$2a+15abc+4$

Step-by-step explanation:

$(2a-16abc-45)+(2a+7abc+11)$

$\implies 2a-16abc-45+2a+7abc+11$

collect and combine like terms:

$\implies 4a-9abc-34$

$(6a+6abc-30)-(4a-9abc-34)$

Apply the distributive law $-\left(a-b\right)=-a+b$:

$\implies 6a+6abc-30-4a+9abc+34$

collect and combine like terms:

$\implies 2a+15abc+4$