Question

3a-2/3+2a+3/2=a+7/6.find a ​

Answer 1

I think your question seems to be ;

${\:\implies \quad \sf 3a-\dfrac23 +2a+\dfrac32 =a+\dfrac76}$

So I will be solving for that ;

${\:\implies \quad \sf 3a+2a+\left(\dfrac32 -\dfrac23\right)=a+\dfrac76}$

${\:\implies \quad \sf 5a+\left(\dfrac{9-4}{6}\right)=a+\dfrac76}$

${\:\implies \quad \sf 5a+\dfrac56 =a+\dfrac76}$

${\:\implies \quad \sf 5a-a=\dfrac76 -\dfrac56}$

${\:\implies \quad \sf 4a=\dfrac{7-5}{6}}$

${\:\implies \quad \sf 4a=\dfrac26}$

${\:\implies \quad \sf 4a=\dfrac13}$

${\:\implies \quad \sf a=\dfrac{1}{3\cdot 4}}$

${\:\implies \quad \bf \therefore \quad \underline{\underline{a=\dfrac{1}{12}}}}$