Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Answer:
2x-6 I think
Step-by-step explanation:
Answer:
3.8333... ft
Step-by-step explanation:
1 ft = 12 inches
46 inches * (1 foot)/(12 inches) = 3.8333... ft
<span>This is asking for a linear function. The base pay is $150, so even if she sells nothing, she cannot be paid less than $150. Because of this, we make that out y-intercept. The number of appliances sold is a variable, so we make that the "X" and multiply that by the amount made ($45) on each additional item sold. You then follow the Order of Operations (PEMDAS) to make your equation.</span>
