The value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
We know that the diagonal of the rectangle bisect each other.
AE = CE
36 = 2x - 4
2x = 40
x = 20
Thus, the value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.
Learn more about the rectangle here:
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Answer: Mark has 28 marbles while Don has 85 marbles.
Step-by-step explanation:
Let x represent the number of marbles that Mark has.
Let y represent the number of marbles that Don has.
If Don has 1 more than 3 times the number of marbles Mark has, it means that
y = 3x + 1
The total number of marbles is 113. It means that
x + y = 113- - - - - - - - - - - - 1
Substituting y = 3x + 1 into equation 1, it becomes
x + 3x + 1 = 113
4x + 1 = 113
4x = 113 - 1 = 112
x = 112/4
x = 28
y = 3x + 1 = 3 × 28 + 1
y = 85
Answer:
4m
Step-by-step explanation:
the ratio to find a square’s area is <em>side length</em> times <em>side length</em>, i.e.
sl * sl = a
2m * 2m = 4m
hope this helps!
how many times does 5 go into 78
78/5
it goes 15 times with 3 left over (15*5 = 75 75+3 = 78)
15 3/5 ft
Answer:
D. The equations do not have the same solution because the second eqlition can never be obtained when multiplying the first
equation by any value
Step-by-step explanation:
-21=14 Equ(1)
6.1=-42 Equ(2)
Multiplying the first equation by -3 will give
-63= -42
Which is not equivalent to the second equation
Multiplying the first equation by 3, we have
-63=42
Not equivalent to the second equation
Multiplying both sides of the first equation by -4, we have
84=56
Not equivalent to the second equation
D. The equations do not have the same solution because the second eqlition can never be obtained when multiplying the first
equation by any value
