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Alexxx [7]
3 years ago
9

Drag the expressions to the boxes to order them from least to greatest? connexus

Mathematics
2 answers:
inessss [21]3 years ago
8 0

Answer:

numbers plz

Step-by-step explanation:

i will prob edit my answer if u put the numbers

puteri [66]3 years ago
5 0

Answer:aadadadStep-by-step explanation:Numbers please?

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Simplify (x^-2y^6/x^-4y^8)1/2
AlexFokin [52]
Simplify the following:
(y^6 y^8)/((2 x^2)/(x^4))
Combine powers. (y^6 y^8)/((x^2×2)/x^4) = (y^(8 + 6) x^(4 - 2))/2:
(y^(8 + 6) x^(4 - 2))/2
8 + 6 = 14:
(y^14 x^(4 - 2))/2
4 - 2 = 2:
Answer: (y^14 x^2)/2
6 0
3 years ago
A sector of a circle of 7cm has an area of 44cm².calculate the angle of the sector,correct to the nearest degree π =22\7​
Hitman42 [59]

Answer:

\theta=102.85^{\circ}

Step-by-step explanation:

Given that,

The radius of circle, r = 7 cm

The area of sector, A = 44cm²

We need to find the angle of the sector. The formula for the area of sector is given by :

A=\dfrac{\theta}{360}\pi r^2

Solve for \theta.

\theta=\dfrac{360A}{\pi r^2}\\\\\theta=\dfrac{360\times 44}{\dfrac{22}{7}\times 7^2}\\\\\theta=102.85^{\circ}

So, the angle of the sector is equal to 102.85^{\circ}.

7 0
3 years ago
Suppose that 6 people sitting in a enclosed room are each generating about 400 BTUs of body heat per hour. If the room is 20 ft
Crazy boy [7]

Answer:  B) 4 BTUs/ft^3

Step-by-step:

For a cuboid of length L, width W and height H, the volume is:

V = L*W*H

In this case, we have:

L = 20ft

W = 15ft

H = 10ft

Then the volume of the room is:

V = 20ft*15ft*10ft = 3000 ft^3

Now we have 6 people, and each generate 400 BTUs per hour.

Then in total, they generate:

6*400 BTUs per hour

2400 BTUs per hour.

Now we want to find the BTUs per ft^3 produced in 5 hours.

Then if they generate 2400 BTUs per hour, in 5 hours they generate a total of:

5*2400 BTUs = 12000 BTUs

Now we take the quotient between the total BTUs and the volume of the room:

Q = (12000 BTUs)/(3000 ft^3) = 4 BTUs/ft^3

The correct option is B.

8 0
3 years ago
H(1)=-35<br><br>h(n)=h(n-1)*2<br><br>h(3)=
Nastasia [14]

Answer:

+

Step-by-step explanation:

3 0
3 years ago
D3<br> Find two numbers between 100 and<br> 150 that have a HCF of 22.
vesna_86 [32]

The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

<h3>Highest common factors</h3>

The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

According to the question, we are to find two numbers between 100 and

150 that have a HCF of 22.

In order to do that we will<u> multiply 22 by the values 5 and 6</u>

First number = 22 * 5 = 10

Second number = 22 * 6 = 132

Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132

Learn more on HCF here; brainly.com/question/21504246

#SPJ1

4 0
2 years ago
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