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jekas [21]
3 years ago
11

Express your answer in scientific notation. 1.8x 10^-2 – 3.9 x 10^-3 =

Mathematics
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

1.41 x 10^-2

Step-by-step explanation:

1.8 x 10^-2 - 3.9 x 10^-33 = 18 x 10^-3 - 3.9 x 10^-3

                                        = (18-3.9) x 10^-3

                                        = 14.1 x 10^-3

                                        = 1.41 x 10^-2

Comment below if you have any questions! If you could mark this answer as the brainliest I would appreciate it!

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The value of a phone when it was purchased was $500. It loses 1/5 of its value a year. What is the value of the phone after 1 y
Ulleksa [173]

es$4 00ya que si divides 500 enlos 5 ted  a  100

4 0
3 years ago
Which expression is equivalent to 1/6 - 3/8 + 1/2
serg [7]

Answer:

7/24

Step-by-step explanation:

1/6-3/8+1/2

4/24-9/24+12/24

-5/24+12/24

7/24

3 0
2 years ago
How many days will it take for a sum of $4,000 to earn $80 interest if it is deposited in a bank paying ordinary simple interest
Maksim231197 [3]

Answer:

It will take 146 days to earn an interest of $80.

Step-by-step explanation:

The simple interest formula is:

I=\frac{P\times r\times t}{100}

It is provided that:

I = $80

P = $4,000

r = 5% p.a.

Compute the time required as follows:

I=\frac{P\times r\times t}{100}

t=\frac{I\times 100}{P\times r}

  =\frac{80\times 100}{4000\times 5}\\\\=0.4\ \years\\\\=0.4\times 365\ days\\\\=146\ days

Thus, it will take 146 days to earn an interest of $80.

4 0
3 years ago
Simplify (3x^-2y^4)^-3
Anuta_ua [19.1K]

Answer:

x^6/27y^12

Step-by-step explanation:

(3. 1?x^2 y^4)^3

(3y^4/x^2)^3

witch you get x^6/27y^12

hope i helped

5 0
3 years ago
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all
posledela

This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

0.7762

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Population mean = 6.20 bl/s

Standard deviation = 1.58 bl/s.

x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

P(x<5) = 0.22378

P(x>5) = 1 - P(x<5)

= 1 - 22378

= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

5 0
3 years ago
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