All categories

3 years ago

Solve the equation: 2x + 6 = 7x - 14

Mathematics

2 answers:

I am Lyosha [343]3 years ago

6 0

Answer:

x = 4

Step-by-step explanation:

2x + 6 = 7x - 14

-7x -7x

-5x + 6 = -14

- 6 - 6

-5x = -20

/-5 /-5

x = 4

Check your answer:

2x + 6 = 7x - 14

2(4) + 6 = 7(4) - 14

8 + 6 = 28 - 14

14 = 14

This statement is true

Hope this helps!

Anika [276]3 years ago

3 0

5x=20
x=4
(move variables and the numbers around in the first step then simplify)

You might be interested in

If you disssolved 50 g of sugar in 30 g of water what would the sugar concentration be

Lelu [443]

<h3>Answer: 62.5%</h3>

Explanation:

There are 50+30 = 80 grams of sugar and water mixed together.

The percentage of sugar is 50/80 = 5/8 = 0.625 = 62.5%

5 0

3 years ago

Can anyone help a fellow out ?

Annette [7]

Cos(44°) = 90/ x
x = 125.1147
-
the length of the string is 125.1147 feet

5 0

3 years ago

Help 26-1x6 ASAP hurry

Ronch [10]

Answer: 20

Step-by-step explanation: Lets break down the problem;

You always use multiplication first when solving an expression.

26 - 1 x 6

1 x 6 = 6

26 - 6 = 20

7 0

4 years ago

How do i add 21p to 35q

mariarad [96]

I don't think you can because the variables are different. You can only add the same variables.

7 0

3 years ago

Read 2 more answers

Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i

earnstyle [38]

$S$ would be a basis for $\mathbb R^3$ if

(1) the vectors in $S$ are independent, and

(2) the vectors span $\mathbb R^3$ .

Linear independence requires that $c_1=c_2=c_3=0$ is the only solution to

$c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)$

These vectors are not linearly independent because if $c_1=3$ , $c_2=1$ , and $c_3=0$ , we have

$3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)$

so $S$ is not a basis for $\mathbb R^3$ .

7 0

3 years ago