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agasfer [191]
3 years ago
9

PLease help me this is due at midnight!

Mathematics
2 answers:
wel3 years ago
6 0
What do you need help with? Please give me a photo or something so that I can help you with it. All I see is “Please help me, this is due at midnight!!” Next time please give US a picture or something so I can be able to help you, Thank you, Sincerely Unknown.
rusak2 [61]3 years ago
3 0
I have no idea how to do this question or anything I just want to answer for the points so my bad
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Multiply the following and provide the product in standard from thank you
LekaFEV [45]

Answer:

x^3 + 4x^2 - 7x - 10

Step-by-step explanation:

To solve this we're going to use Polynomial multiplication, starting by multiplying (x-2)(x+1) = x^2 - 2x + x - 2 = x^2 - x - 2. Next, we will multiply (x^2 - x - 2)(x+ 5) = x^3 + 5x^2 -x^2 - 5x -2x -10 = x^3 + 4x^2 - 7x - 10.

8 0
3 years ago
How do you use the additive inverse to evaluate an expression that uses subtraction?
Harlamova29_29 [7]
You use additive inverse to combine like terms that are on opposite sides of the equation. 
ie.
3x + 1 = 6x -12 
You use additive inverse to move -12 to the +1
3 0
4 years ago
Read 2 more answers
Please help!!! i will mark brainliest and i need a little bit of explanation!!
Mazyrski [523]

Answer:

e

Step-by-step explanation:

it is e because 2 hours is speed is 40 4 hours speed is i0

8 0
3 years ago
The circle described by the equation <img src="https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%28y%2B4%29%5E%7B2%7D%3D9" id="T
ElenaW [278]

Answer:

The point at which center of the image circle located is (-2, -3) so second option is correct.

Step-by-step explanation:

Given equation of circle is:

(x-3)^{2} + (y+4)^{2} = 9 (i)

The general equation of circle is mentioned below,

(x-h)^{2} + (y-k)^{2} = r^{2} (ii)

Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.

By comparing equation (i) and equation (ii), we get

r^2 = 9

r = 3

(x-3)^{2} = (x-h)^{2}

(x-3) = (x-h)

h = 3

(y+4)^{2} = (y-k)^{2}

(y+4) = (y-k)

k = -4

So the center of given circle is (h,k) = (3,-4)

Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2

Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3

Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.

6 0
3 years ago
Read 2 more answers
Pls someone answer me in correct way
pogonyaev
2nd line:
output y=0, ordered pair (0, 0)
3 0
4 years ago
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