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sergij07 [2.7K]

3 years ago

8

sally decided she wanted homework help. no one gave it to her. if over 100 people were on the app to help and 1 person helped ho

w many people are helpless?

2 answers:

olga2289 [7]3 years ago

7 0

Answer:

thats so deep

<em>i</em><em> </em><em>see</em><em> </em><em>where</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>coming</em><em> </em><em>from</em><em> </em><em>and</em><em> </em><em>i</em><em> </em><em>see</em><em> </em><em>ur</em><em> </em><em>point</em>

<em>ppljust</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>stop</em><em> </em><em>being</em><em> </em><em>selfish</em><em> </em><em>an</em><em> </em><em>helo</em><em> </em><em>eachother</em><em> </em><em>wetre</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>pandemic</em><em> </em><em>for</em><em> </em><em>christs</em><em> </em><em>sake</em>

Irina-Kira [14]3 years ago

4 0

All people but the 1

You might be interested in

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

The Z-score is based on the concept of the normal distribution, the fact that we can expect 95% of the values in the distributio

Dennis_Churaev [7]

Answer:

C.) In perfect health.

Step-by-step explanation:

Given an average weight of 15kg and a standard deviation of 3kg for children of 4 years. Since the weight is based on a normal Z - distribution of 95% which is mean ± 2(standard deviations)

Mean weight interval is :

15 - 2(3) ; 15 + 2(3)

(9 ; 21) ; this weight interval could be interpreted to mean the normal or perfect weight value.

Therefore, given that the child weighs 12kg

Since, 12 kg falls within in the interval, we can conclude that the child is in perfect health.

7 0

3 years ago

How many different rays can be formed from five collinear points?

spayn [35]

Answer:

I believe that its infinitely

4 0

3 years ago

Read 2 more answers

If the price of a purse increased from $45 to $54, what was the percent of increased

pishuonlain [190]

54-45/45 x 100%
= 20%

5 0

3 years ago

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Estimate 2000 ÷3.67

inysia [295]

Answer:

1.30

Step-by-step explanation:

2000^3.67 =1.3025071e+12

3 0

3 years ago

Read 2 more answers