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Marianna [84]
3 years ago
14

How do you do this? Because i don't know how to do it :>

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

£ 7.95

Step-by-step explanation:

Let the total money = £ x

Money spend on drinks and cake = 1.45 + 1.20 = £ 2.65

Money left with her = (2/3) of x

So, money spend = (1/3) of x

\dfrac{1}{3}*x= 2.65\\\\\\x=2.65*3\\\\

x = £ 7.95

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A present age for a is idk srry dude 
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Two nickels are flipped and a number cube is rolled. How many total outcomes are there?
Taya2010 [7]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the equation of the graphed function?
masya89 [10]
The correct answer is A.) f(x)=\frac{-1}{3}x+1

This is because using slope intercept form (y=mx+b), we can solve.

m = slope
b= y-intercept

If you look at the graph, you can see the line crosses they y-axis at 1.

And if you follow the line using rise over run, you find that it is 1/3.
But because it is a negative line, it makes the slope negative.

Hope this helps!
8 0
3 years ago
Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f
schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval:  (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{130}{20} = 6.5

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

S.D = \sqrt{\frac{233.5}{19}} = 3.50

b) Standard Error

= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826

c) Point estimate for the mean time required for all college is given by the sample mean.

\bar{x} = 6.5

d) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0
4 years ago
A new company opens and finds the profits from their first year in business is $24,000. They project the company's profits to in
Fiesta28 [93]

Answer:

$4406.7 is the profit.

explanation:

compound interest formula: \sf \large\boxed{\sf P(1+\frac{r}{100})^n }

using this formula:

\rightarrow \ \sf \sf 24000(1+\dfrac{1.7}{100})^{10} }

\rightarrow \sf \ $ \sf 28406.7

profit: $28406.7  - $24,000 = $4406.7

8 0
3 years ago
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