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Marianna [84]
2 years ago
14

How do you do this? Because i don't know how to do it :>

Mathematics
1 answer:
Sindrei [870]2 years ago
7 0

Answer:

£ 7.95

Step-by-step explanation:

Let the total money = £ x

Money spend on drinks and cake = 1.45 + 1.20 = £ 2.65

Money left with her = (2/3) of x

So, money spend = (1/3) of x

\dfrac{1}{3}*x= 2.65\\\\\\x=2.65*3\\\\

x = £ 7.95

You might be interested in
5 ft is ____ % of 37 1 2 ft; 37 1 2 ft is ____ % of 5 ft
hichkok12 [17]

Answer:

The answer is:

5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

Step-by-step explanation:

Given:

5 ft is ____ % of 37 1 2 ft.

Now, to find the __ :

Let __ be x.

So, 5 ft is x\% of 37 1/2

5=x\% of 37\frac{1}{2}

⇒ 5=\frac{x}{100} \times \frac{75}{2}

⇒ 5=\frac{75x}{200}

Multiplying both sides by 200 we get:

⇒ 1000=75x

Dividing both sides by 75 we get:

⇒ 13.33=x

⇒ x=13.33\%.

Now, 37 1/2 ft is x% of 5 ft.

\frac{75}{2} =x\%\ of\ 5

\frac{75}{2}=\frac{x}{100}\times 5

\frac{75}{2} =\frac{5x}{100}

Multiplying both sides by 100 we get:

\frac{7500}{2} =5x

Dividing both sides by 5 we get:

750=x

x=750\%

Therefore, the answer is 5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

8 0
3 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Can someone pls help​
Lunna [17]
Answer:
y intercept: (0,2)
explanation:

4 0
3 years ago
Add the integers.<br> -6 + (-4) =( ?<br> B-2<br> C 2<br> D 10
lina2011 [118]
Answer:
-6 + -4 = -10
3 0
3 years ago
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Sam collected six leaves to feed to his caterpillar collection if he wanted to split the leaves among seven cages how much shoul
Kazeer [188]
6÷7 is 0.857. maybe?
3 0
3 years ago
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