All categories

3 years ago

Help pleaseee mathhhhhh

Mathematics

1 answer:

dimaraw [331]3 years ago

5 0

Answer:

hehjzjxjxjdjjdhdhdhdhjdjdjhdhdhdhdjdjjdjsjs B is correct

You might be interested in

What is 3 divided by 320 equal?

inna [77]

$\tt{Hey~there!$

$\tt{3\div320$

$\tt{Divide~the~two~numbers:$

$\tt{3\div320=0.009375$

$\boxed{\tt{0.009375}}$

$\tt{Hope~this~helps!$

$\boxed{\tt{-TestedHyperr}}$

6 0

3 years ago

Luz earns $400 for 40 hours of work. Use a ratio table to figure out how much she earns for 6 hours of work

GrogVix [38]

Hours of work: 40....20....10....6 Payment per hours: 400....200...100...60 Or Hours of work:2....4....6 Payment per hours:20....40....60. Luz earns 10 dollars per hour.

4 0

3 years ago

She has saved $30 which is three fifths of the total cost, how much is the total cost

drek231 [11]

Answer:

$50

Step-by-step explanation:

3/5=30/x

x= The total cost

You can see that 3×10 multiplies to 30, so the total cost would be 5×10.

Total cost= 50

4 0

3 years ago

Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin

Sidana [21]

Answer:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

6 0

3 years ago

Read 2 more answers

PLEASE HELP! (Correct answers only please)

Licemer1 [7]

23440 & 2.344 x 10^4

5 0

3 years ago