Divide the recipe by 4. You need 4 cups of water.
This is not a polynomial equation unless one of those is squared. As it stands x=-.833. If you can tell me which is squared I can help solve the polynomial.
Ok, that is usually notated as x^3 to be clear. I'll solve it now.
x^3-13x-12=0
Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1
Then you have x^2-x-12 now you complete the square.
Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:
The x-term coefficient = −1
The half of the x-term coefficient = −1/2
After squaring we have (−1/2)2=1/4
When we add 1/4 to both sides we have:
x2−x+1/4=12+1/4
STEP 3: Simplify right side
x2−x+1/4=49/4
STEP 4: Write the perfect square on the left.
<span>(x−1/2)2=<span>49/4
</span></span>
STEP 5: Take the square root of both sides.
x−1/2=±√49/4
STEP 6: Solve for x.
<span>x=1/2±</span>√49/4
that is,
<span>x1=−3</span>
<span>x2=4</span>
<span>and the one from before </span>
<span>x=-1</span>
Answer:
part 1) It takes 2/15 hour to complete 1 task
Part 2) The robot can only complete 7 tasks in an hour (the remaining doens’t count)
Step-by-step explanation:
So first divide to find unit rate
2/5 ÷ 3
2/5 * 1/3
2/15
For part 2
Just put the unit rate in an equation
2/15x=1
Where 1 is the single hour and x is the task
solve
you’ll get 7 1/2
Due to only requesting for tasks in an Hour
its only 7 task
The unit rate of 200 miles in 4 hours is 50 miles for every 1 hour.
200/4 divided by 4/4 = 50/1
The unit rate of 270 miles in 6 hours is 45 miles for every 1 hour.
270/6 divided by 6/6 = 45/1
The unit rate of 1440 miles in 30 hours is 48 miles for every 1 hour.
1440/30 divided by 30/30 = 48/1
Answer:
What equation? Here’s a big tip for you, equations contain an ‘equals sign’ (‘=’) and something that they are equal to. I’m assuming your equation is:
ax2+bx+c=0
I’m going to use p and q for the roots of the equation as they are easier to type than α and β . Thus we have:
a(x−p)(z−q)=0⇒ax2−a(p+q)x+apq=0
Equating coefficients with our initial equation:
x1 : b=−a(p+q)⇒p+q=−ba
x0 : c=apq⇒pq=ca
Now p2+q2=p2+2pq+q2−2pq=(p+q)2−2pq
=(−ba)2−2ca
=b2a2−2ca
=b2−2aca2