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Lorico [155]
2 years ago
8

Write down the fixed monthly electricity cost for the prepaid system

Mathematics
2 answers:
ale4655 [162]2 years ago
7 0

Answer :

A prepaid electricity meter is a Kw/hr (Kilowatt Hour) meter, measuring electrical consumption. The main difference is that this Kw/hr meter counts backwards as the electricity is consumed and has a a relay (an automatic switch) which disconnects the power when the Kw/hr reading on the meter reaches zero.

tatuchka [14]2 years ago
4 0
Answer

Prepaid meters work on a system whereby the consumer pays upfront for the service. No money, no service. Residents on credit meters used to having 60 days to pay for electricity will now have to pay upfront before electricity is used

Answer #2

The more you use, the more you pay per block. So if you pay as you go through the month, or pay for more power than you need, you will end up paying more, but not getting more units on average.

Answer #3

Prepaid electricity rates per unit 2021 South Africa. Prepaid electricity rates for users who Eskom directly charges is R158. 36 (inclusive of VAT) for every 0-600kWh.

Step-by-step explanation

A new meter costs roughly R600 and installation should not exceed R1 000, according to installers in other municipalities. Converting to prepaid in eThekwini costs R2 010, which is affordable, and even in Msunduzi the cost is less than uMngeni at about R4 000.

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Dennis_Churaev [7]

Answer:

D^1 should be (28,0)

Step-by-step explanation:

a dilation is performed by multiplying the x and y coordinates by the scale factor. D(7,0)... (7×4,0×4).... D^1(28,0)

4 0
3 years ago
The first car of the D-line train carried 1.5 times the number of passengers that the second car carried. Three passengers get o
kondor19780726 [428]

Answer:

the first car has 15 passengers and the second has 10

Step-by-step explanation:

7 0
3 years ago
Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.
svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
6 0
2 years ago
Ahmed drive his car 4 hours continuously as average 80 Km/hr .if his speed was 60 Km in the 1st hour, 90 Km in the 2nd hour and
nadezda [96]

Answer:

I would say 120 but that could be also be wrong but ill go with 120

7 0
2 years ago
I need help that is simple enough explnation
velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
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