The equation of a circle is given as:
(x-a)^2 + (y- b)^2 = r^2 where (a, b) is the center.
(x-9)^2 = x^2 -18x + 81 - ----(i)
(y+2)^2 =y^2 + 4y +4 ------ (ii)
r^2 = 49 ------ (iii)
Adding equation (i) and (iii)
x^2 + y^2 - 18x + 4y + 85 -----(iv)
Equating equation (iv) and (iii)
<span>x^2 + y^2 - 18x + 4y + 85 = 49
Arrange the equation:
</span> <span>x^2 + y^2 - 18x + 4y + 36 = 0
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I hope this helps
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Answer:
The three consecutive integers are 5,6,7
Step-by-step explanation:
Let the three consecutive integers be represented as x,x+1,x+2
As per the requirement, largest integer is 3 less than twice the smallest.
=> x+ 2 = 2x -3
=> 2x -x = 2+3
=> x= 5
So the three integers are 5,6,7
Verification:
Largest integer = 7
Smallest integer = 5
2 * smallest integer - 3 = 2* 5 - 3 = 7
Largest integer is also 7.
So the required condition in the question is satisfied by these three integers.
Answer:
Step-by-step explanation:
-1/6 * -1/5 = 1/30
A negative number times a negative number equals a positive number. When multiplying fractions, the numerators get multiplied over the denominators being multiplied. so -1 * -1 = 1 which is the numerator. 6 * 5 is 30 which is the denominator.
The length is (3/5 -1/5)=2/5
the height is also 2/5
area: length * height =2/5 *2/5=4/5
D is correct.
Answer:
Step-by-step explanation:
The Fundamental Theorem of Algebra states that the number of complex roots a polyomial has is equal to its highest exponent. This is a squared polynomial; second degree; quadratic. When it is factored, no matter what types of numbers you get as the solution, you will ALWAYS have 2 of them. When this quadratic is factored, we get that x = 3 and x = 3. That means that this is a quadratic that touches the x-axis at (3, 0). It doesn't go through, it only touches. We do have 2 roots, but since they're the same, we say we have a multiplicity 2 of that root. The closest you'll come to that in your choices is A. Apparently your text refers to multiplicity 2 as a double root.
