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3 years ago

What is the volume of a cone with a radius of 6 and a slant height of 10?

Mathematics

1 answer:

kykrilka [37]3 years ago

4 0

Answer:

301.59289

Step-by-step explanation:

V=1/3pi r^2 Sq. root l^2- r^2= 1/3pi x 36 x Sq. root 100-36= 1/3pi x 144= 301.59289

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What is the slope of a line perpendicular to the line: y = -2/3x + 5

Rus_ich [418]

1.5

Opposite reciprocal of -2/3

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3 years ago

Find the value (18 9) / 3d for d=3

Alexeev081 [22]

Assuming that you ment- (18*9)/3d where d=3 you would follow PEMDAS-
Parentheses
Exponents
Multiplication-Division (in order from right to left)
Addition-Subtraction (in order from right to left)
1. Parentheses- (18*9)=162
2. Solve your variables- 3d (3*3)=9
Giving you- 162/9
3. Solve-162/9=18

7 0

3 years ago

What way of warming up is preferred before exercise? *

oksano4ka [1.4K]

Answer: B!

Step-by-step explanation: The best way to warm up before taking part in physical activity is to perform low-intensity, dynamic movements that are similar to the main type of activity that you will perform.

7 0

2 years ago

Read 2 more answers

PLEASEEEEEE HELPPPPPPPPP!!!!!!!!!!!!!!!!! ON ASSESSMENTTTT PRACTICEEEE ITS VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Find the co

adelina 88 [10]

In order to determine the vertex of the given functions, consider that the general form of a quadrati function is:

y = ax² + bx + c

The value of x for the vertex is given by:

x = -b/2a

The value for y, based on the previous values of x, is the y value of the vertex. Use the previous expression to find the vertices:

1. y = x² + 8x - 6

x = -8/2(1) = -4

y(-4) = (-4)² + 8(-4) - 6 = 16 - 32 - 6 = -22

Hence, the vertex is (-4,-22)

2. y = -4x² - 24x - 5

x = -(-24)/2(-4) = -6

y(-6) = -4(-6)² - 24(-6) - 6 = -144 + 144 - 6 = -6

Hence, the vertex is (-6,-6)

3. y = 2x² - 3x + 7

x = -(-3)/2(2) = 3/4 = 0.75

y(3/4) = 2(3/4)² - 3(3/4) + 7 = 18/16 - 9/4 + 7 =5.875

Hence, the vertex is (0.75 , 5.875)

4. y = -x² + 5x - 6

x = -5/2(-1) = 5/2 = 2.5

y(5/2) = -(5/2)² + 5(5/2) - 6 = 0.25

Hence, the vertex is (2.5 , 0.25)

5. y = 1/2 x² + 6x - 5

x = - 6/(2(1/2)) = -6

y(-6) = 1/2 (-6)² + 6(-6) - 5 = -23

Hence, the vertex is (-6 , -23)

6. y = 4x² + 7

x = -0/2(4) = 0

y(0) = 4(0) + 7 = 7

Hence, the vertex is (0 , 7)

8 0

1 year ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago